Circumference of a circle = Pi x diameter
The amount of distance covered by a wheel in one rotation is equal to the circumference (assuming no slippage), and therefore a 2" wheel will rotate at 1/2 the RPM of a 1" wheel to move forward at the same speed.
Assume a slot car tire of 3/4" (0.750) per USRA rules (and because it makes the math easier than doing the D3 size)
averaging 70 MPH, and a 1/8 scale R/C car with 3-3/8" (3.375) tires averaging 50 MPH. (I couldn't find any rules for 1/8 scale R/C wheel size when I Googled it, so I assumed a 1/24 "true scale" tire of 1-1/8" would be 3 times as large in 1/8 scale.)
The slot car is moving at (7/5) the speed of the RC car (1.4 times as fast).
The slot car's wheels must rotate at (3.375/0.750) or 4.5 times the RPM to move ahead at the same speed.
The combination of the two (smaller wheels, faster average speed) means that the slot car's tires will be rotating at (1.4 * 4.5) or 6.3 times the RPM of the larger R/C car's wheels.
However, the "centrifugal force" (yeah, I know, I should work out the vectors for the tire at the circumference attempting to continue at a tangent, but I'm too tired right now) increases with diameter, I think that the only necessary comparison is the relative speeds of the two vehicles, since that would determine the speed of the tire surface at the circumference. Since the slot car is 40% faster, and momentum increases by the square of the speed (quadruples when the speed doubles), that means that the relative momentum should be (1.4 * 1.4) for the slot car, or 196% of the force on the RC car's tires.
So an adhesive which might be perfectly adequate for the RC car's tires would be subject to approximately double the force if used on a slot car tire.
I think my head hurts...